|
The Book of Lemmas: Proposition 3
|
Main Concept
|
|
Let D be any point on a segment of a circle whose base is AB and let DE be perpendicular to AB. Take C on AB so that AE = EC. If now DF is an arc equal to the arc AD, and BF is joined, then BF, BC shall be equal.
|
|
|
Adjust the slider, or click and drag on the plot to change the value of D.
|
|
|
D =
|
|
|
|
Download Help Document
Was this information helpful?
