The range command returns random integers from a range defined with a step size.

The range(n) command, where n>=1, generates a random integer in the range 1, ..., floor(n) (inclusive).  There are floor(n) numbers in that range. Hence, it is a selection of one number from a choice of floor(n).

With 2 arguments, range(m,n), where n-m>=0, generates a random integer in the range m, m+1,..., m+q (inclusive) where q is the floor of n-m

With 3 arguments, range(m,n,k), where (n-m)/k=0 generates a random integer in the range m, m+k, ..., m+qk (inclusive) where q is the floor of (n-m)/k.  That is, range(n) = range(1,n) = range(1,n,1)

Note: The rint function returns random numbers in the range 0, ..., n-1 (inclusive).

$\left\{\mathrm{seq}\left(\mathrm{MapleTA}:-\mathrm{Builtin}:-\mathrm{range}\left(3\right)\,i\=1..100\right)\right\}$

$\left\{1\,2\,3\right\}$

$\left\{\mathrm{seq}\left(\mathrm{MapleTA}:-\mathrm{Builtin}:-\mathrm{range}\left(2\,3\right)\,i\=1..100\right)\right\}$

$\left\{2\,3\right\}$

$\left\{\mathrm{seq}\left(\mathrm{MapleTA}:-\mathrm{Builtin}:-\mathrm{range}\left(0\,7\,3\right)\,i\=1..100\right)\right\}$

$\left\{0\,3\,6\right\}$

$\left\{\mathrm{seq}\left(\mathrm{MapleTA}:-\mathrm{Builtin}:-\mathrm{range}\left(0\,8\,3\right)\,i\=1..100\right)\right\}$

$\left\{0\,3\,6\right\}$

$\left\{\mathrm{seq}\left(\mathrm{MapleTA}:-\mathrm{Builtin}:-\mathrm{range}\left(0\,9\,3\right)\,i\=1..100\right)\right\}$

$\left\{0\,3\,6\,9\right\}$

$\left\{\mathrm{seq}\left(\mathrm{MapleTA}:-\mathrm{Builtin}:-\mathrm{range}\left(1\,10\,3\right)\,i\=1..100\right)\right\}$

$\left\{1\,4\,7\,10\right\}$

The MapleTA[Builtin][range] command was introduced in Maple 18.

For more information on Maple 18 changes, see Updates in Maple 18.