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Tg[]gwpV]B^jN?qxPvOvtWviGisuwuu?j[?uR_[mFaGakQ>^jq\\I`pGqnloZFAZBguX`bbYk;GeXhfUao;V`:guxGgaAajgm<V`[X^V_uxvivWw^_`Vfd[WhkQtsabFv^MI]OXqHyervlHgnEhjofxHyasVy^__PV_diZeYxayiDWtGWZ`WuUylbpb=I`qh]yioqpykaflfy<yvy@glOmSvdVyywXrKPcHqkWQxs_iR?i@y^VvsgOw`yZZ>lAGiTp^rFg`hr;ivkVvLpjn^w^I[gf[e`dD?j=YooO_=`^gHtbhgho]mIyvQoKNh[QrshogXv[@t<g[]qrUvcY`iOImmx[x>gsAsA^cHW`]ib>qiS`tfXcMRekvnovO;s>AvYiSwEbFqwxqWaWuSUtissWwycgshAIsMx_KUPmXxagvKEWUXGiXd[sX_YlIhTegtMwNiCd[spmGYmVSmtrmdqaYnYbIeInAtOOyaiHQMbTGxm[YXSufUxF=g<qRG[GDgR<QuDgt@Uh;wFkAEPST;CyrYDIgEYaIXHmxauMtSwlYoitiTrM`jTxMxdynYlCaJX@SHaSNaWpTpwYvAxmx\\oXaX`qRMXtFAP]IM=@SLlYW\\j]ItbaxoyonYywQoTaOOmKiMQwQOOpPedpDqshqsGttyPlBENaej`HW]qKyHy[xKPmMx=tNuk`=mkYp@Pufe^r__kgsE_p_yfAfn=FoefqVwp@o]u_wkHi^hmsVh`ItAw]oft]H]`_yiWZ^pfVVttirHymyvigipQqr]Y[UOsDQpvarIpinOw`X``vnSlSIkMxNouxLpni\\UJqSg\\y]XuxlxGyOwYjcpMGAP]IuI<noXLa\\p`LlxuqyMwNIomxVIQmBUP=akaQOrmmq=axGyWvwvOyUyytgjwQg`gvTakaId>XrbpspOyFI]rQq<qioxy<Fq<GlpWlcQgh@Z:>Z:Fc?oc>oo<?f<3<</Image><Font bold="true" encoding="ISO8859-1" family="Times New Roman" underline="false">M\351thodes num\351riques pour
                  les \351quations diff\351rentielles:</Font></Text-field><Text-field layout="_pstyle257" style="_cstyle258"><Font encoding="ISO8859-1" family="Times New Roman">M\351thode d'Euler-Cauchy</Font></Text-field><Text-field layout="_pstyle264" style="_cstyle297"><Font encoding="ISO8859-1" family="Times New Roman">M\351thode de Heun</Font></Text-field><Text-field layout="_pstyle265" style="_cstyle298"><Font encoding="ISO8859-1" family="Times New Roman">M\351thode de Runge-Kutta</Font></Text-field><Text-field layout="_pstyle263" style="_pstyle263"/><Text-field layout="Author" style="ParagraphStyle1"><Font encoding="ISO8859-1" family="Times New Roman" style="_cstyle262">\251 Pierre Lantagne </Font><Font family="Times New Roman" style="_cstyle264">(avril 2001)</Font></Text-field><Text-field layout="_pstyle258" style="_cstyle260"><Font encoding="ISO8859-1" family="Times New Roman">Coll\350ge de Maisonneuve</Font></Text-field><Text-field layout="_pstyle259" style="_cstyle261"><Font family="Times New Roman">plantag@edu.cmaisonneuve.qc.ca</Font></Text-field><Text-field layout="_pstyle260" style="_cstyle263"><Font family="Times New Roman">http://math.cmaisonneuve.qc.ca/plantagne</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Nous connaissons plusieurs m\351thodes pour la r\351solution</Font><Font family="Times New Roman" style="_cstyle267"> analytique</Font><Font encoding="ISO8859-1" family="Times New Roman"> de certaines \351quations diff\351rentielles du premier ordre et du premier degr\351. Par exemples, pour les</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">\351quations diff\351rentielles \340 variables s\351parables</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">\351quations diff\351rentielles homog\350nes</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">\351quations diff\351rentielles lin\351aires</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">\351quations diff\351rentielles de Bernouilli</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">\351quations diff\351rentielles exactes</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">\351quations diff\351rentielles non exactes</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Mais, il y a plusieurs \351quations diff\351rentielles du premier ordre qui ne poss\350dent pas de solutions analytiques. Pour de telles \351quations, il y a plusieurs m\351thodes d'approximation<Font style="_cstyle299"> num\351riques</Font></Font><Font family="Times New Roman"> :</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">m\351thode d'Euler-Cauchy</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">m\351thode  de Heun (ou m\351thode am\351lior\351e d'Euler-Cauchy)</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font encoding="ISO8859-1" family="Times New Roman">m\351thode de Runge-Kutta</Font></Text-field><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Dans un  premier temps, nous alllons \351prouver la m\351thode d'Euler-Cauchy avec la solution analytique de l'\351quation diff\351rentielle du premier ordre </Font><Equation input-equation="dy/dx = -2*x-y;" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiLCYqJiIiI0YmJSJ4R0YmRiglInlHRig=</Equation><Font family="Times New Roman">.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">restart;</Text-field></Input></Group><Section collapsed="true"><Title><Text-field layout="Heading 1" style="Heading 1"><Font encoding="ISO8859-1" family="Times New Roman"> Champ des \351l\351ments de contact</Font></Text-field></Title><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Une \351quation diff\351rentielle du premier ordre est une \351quation de la forme </Font><Equation input-equation="dy/dx = f(x,y);" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiLSUiZkc2JCUieEclInlH</Equation><Font encoding="ISO8859-1" family="Times New Roman">.  En se rappelant l'interpr\351tation graphique de </Font><Equation input-equation="dy/dx" style="2D Comment">NiMqJiUjZHlHIiIiJSNkeEchIiI=</Equation><Font family="Times New Roman">,  f(<Font style="_cstyle274">x</Font>,<Font style="_cstyle275">y</Font><Font encoding="ISO8859-1">) est donc une formule donnant la pente de la tangente \340 la courbe solution passant par le point (</Font><Font style="_cstyle276">x</Font>,<Font style="_cstyle277">y</Font><Font encoding="ISO8859-1">). Ainsi, l'\351quation diff\351rentielle </Font></Font><Equation input-equation="dy/dx = -2*x-y;" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiLCYqJiIiI0YmJSJ4R0YmRiglInlHRig=</Equation><Font encoding="ISO8859-1" family="Times New Roman"> peut \352tre visualis\351e par un graphique appel\351 <Font style="_cstyle300">champ des \351l\351ments de contact</Font>. Chaque \351l\351ment de ce champ est un petit segment de droite centr\351 au point (</Font><Equation input-equation="x[0],y[0]" style="2D Comment">NiQmJSJ4RzYjIiIhJiUieUdGJQ==</Equation><Font family="Times New Roman">) d'orientation f(</Font><Equation input-equation="x[0], y[0]" style="2D Comment">NiQmJSJ4RzYjIiIhJiUieUdGJQ==</Equation><Font family="Times New Roman">). </Font></Text-field><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Ainsi, pour l'\351quation diff\351rentielle </Font><Equation input-equation="dy/dx = -2*x-y;" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiLCYqJiIiI0YmJSJ4R0YmRiglInlHRig=</Equation><Font encoding="ISO8859-1" family="Times New Roman">, au point (-2,3), la pente de la tangente \340 la courbe solution </Font><Font family="Times New Roman" style="_cstyle301">y</Font><Font family="Times New Roman"> passant par ce point est  </Font><Equation input-equation="`y'` = -2*(-2)-3;" style="2D Comment">NiMvJSN5J0csJiomIiIjIiIiLCRGJyEiIkYoRioiIiRGKg==</Equation><Font encoding="ISO8859-1" family="Times New Roman"> = 1.  Au point (6,2) la pente de la tangente \340 la courbe solution est </Font><Equation input-equation="-14" style="2D Comment">NiMsJCIjOSEiIg==</Equation><Font encoding="ISO8859-1" family="Times New Roman">. Dans le premier cas, on illustre le r\351sultat par un petit segment de droite centr\351 en (-2,3) de pente 1 et, dans le second cas, par un autre segment de droite centr\351 en (6,2) de pente </Font><Equation input-equation="-14" style="2D Comment">NiMsJCIjOSEiIg==</Equation><Font encoding="ISO8859-1" family="Times New Roman">. En r\351p\351tant ce pr\351cessus pour un certain nombre de couples (</Font><Font family="Times New Roman" style="_cstyle278">x</Font><Font family="Times New Roman">,<Font style="_cstyle279">y</Font>), on obtient ce qu'on appelle un <Font encoding="ISO8859-1" style="_cstyle302">champ d'\351l\351ments de contact</Font>, parfois traduit de l'anglais par champ de pente.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">La macro-commande </Font><Font style="_cstyle266">dfieldplot</Font><Font family="Times New Roman"> de l'extension  </Font><Font style="_cstyle268">DEtools</Font><Font encoding="ISO8859-1" family="Times New Roman"> permet le trac\351 d'un champ d'\351l\351ments de contact. L'extension </Font><Font style="_cstyle269">DEtools</Font><Font encoding="ISO8859-1" family="Times New Roman"> impose la formulation explicite de la variable d\351pendante. Dans le cas d'une fonction de deux variables </Font><Font family="Times New Roman" style="_cstyle270">x</Font><Font family="Times New Roman"> et <Font style="_cstyle271">y</Font>, si la variable <Font style="_cstyle272">y</Font><Font encoding="ISO8859-1"> est d\351sign\351e comme d\351pendante, on doit l'\351noncer dans les requ\352tes avec la syntaxe </Font><Font style="_cstyle273">y(x)</Font>.</Font></Text-field><Text-field layout="Normal" style="Normal"><Font family="Times New Roman"> </Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">with(plots):
with(DEtools):</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">ED:=diff(y(x),x)=-2*x-y(x);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Champ:=dfieldplot(ED,[y(x)],
x=-2..2,y=-2..2,arrows=line,dirgrid=[25,25],scaling=constrained,color=orange):
display(Champ);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">On peut \351galement repr\351senter dans un champ d'\351l\351ments de contact, des courbes appel\351es </Font><Font family="Times New Roman" style="_cstyle303">isoclines</Font><Font family="Times New Roman"> ( du grec <Font style="_cstyle280">iso</Font><Font encoding="ISO8859-1"> qui signifie m\352me et du latin </Font><Font style="_cstyle281">clinare</Font><Font encoding="ISO8859-1"> qui signifie pencher). Les isoclines sont des courbes le long desquelles les \351l\351ments de contact ont une direction ( une inclinaison ) donn\351e.</Font></Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Superposer, dans le champ d'\351l\351ments de contact pr\351c\351dent, les isoclines de pente  0 et \2611.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">f:=(x,y)-&gt;-2*x-y;</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">j:=0:
for i in [-1,0,1] do
  iso||j:=implicitplot(f(x,y)=i,x=-2..2,y=-2..2,color=blue):
  j:=j+1:
od:</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"><Font encoding="ISO8859-1">display({iso||(0..j-1),Champ},view=[-1..1,-1..1],title="Isoclines d'\351quations f(x,y)=c");</Font></Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">L'int\351r\352t du champ d'\351l\351ments de contact appara\356t clairement avec l'usage de l'ordinateur. Que l'\351quation diff\351rentielle poss\350de ou non une solution analytique, ce type de trac\351 permet de visualiser l'ensemble des courbes solution de l'\351quation diff\351rentielle. En effet, le champ d'\351l\351ments de contact pr\351c\351dent permet de visualiser ceci:</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font family="Times New Roman">lorsque <Font style="_cstyle282">x</Font> &lt; </Font><Equation input-equation="-y/2" style="2D Comment">NiMsJComJSJ5RyIiIiIiIyEiIkYo</Equation><Font family="Times New Roman">, chaque courbe solution est croissante</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font family="Times New Roman">lorsque <Font style="_cstyle283">x</Font> &gt; </Font><Equation input-equation="-y/2" style="2D Comment">NiMsJComJSJ5RyIiIiIiIyEiIkYo</Equation><Font encoding="ISO8859-1" family="Times New Roman">, chaque courbe solution est d\351croissante</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font family="Times New Roman">lorsque <Font style="_cstyle284">x</Font> = </Font><Equation input-equation="-y/2" style="2D Comment">NiMsJComJSJ5RyIiIiIiIyEiIkYo</Equation><Font family="Times New Roman">, chaque courbe solution admet un maximum relatif</Font></Text-field><Text-field layout="Dash Item ident" style="Dash Item ident"><Font family="Times New Roman">lorsque <Font style="_cstyle286">x</Font> </Font><Font encoding="ISO8859-1" style="_cstyle285">\256</Font><Font family="Times New Roman"> </Font><Equation input-equation="infinity" style="2D Comment">NiMlKWluZmluaXR5Rw==</Equation><Font family="Times New Roman">, toutes les courbes solutions ont un comportement asymptotique</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">Puisque </Font><Equation input-equation="`y'` = x-y;" style="2D Comment">NiMvJSN5J0csJiUieEciIiIlInlHISIi</Equation><Font encoding="ISO8859-1" family="Times New Roman"> est une \351quation diff\351rentielle du premier ordre et du premier degr\351, m\352me s'il est facile d'en obtenir directement la solution par un calcul \340 la main, r\351solvons quand m\352me cette \351quation avec Maple.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">dsolve(ED);</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">La solution g\351n\351rale de cette \351quation est donc</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Sol:=y=-2*x+2+C*exp(-x);</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Superposons au champ d'\351l\351ments de contact pr\351c\351dent, les solutions particuli\350res correspondant aux conditions initiales </Font><Equation input-equation="y(0)=C" style="2D Comment">NiMvLSUieUc2IyIiISUiQ0c=</Equation><Font family="Times New Roman"> pour C =  </Font><Equation input-equation="-2" style="2D Comment">NiMsJCIiIyEiIg==</Equation><Font family="Times New Roman">, </Font><Equation input-equation="-1" style="2D Comment">NiMsJCIiIiEiIg==</Equation><Font family="Times New Roman">, 0, 1 et 2.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Sol:=-2*x+2+C1*exp(-x):
i:=0:
for C in [-2,-1,0,1,2] do 
  C1:=C-2:
  f||i:=plot([x,Sol,x=-2..2],color=navy,thickness=2):
  i:=i+1
od:
C1:='C1':
C:='C':</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">display({f||(0..4),Champ},view=[-2..2,-2..2],title="dy/dx = -2x-y",titlefont=[TIMES,ROMAN,12]);</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">La macro-commande </Font><Font style="_cstyle287">DEplot</Font><Font family="Times New Roman"> de l'extension </Font><Font style="_cstyle288">DEtools</Font><Font encoding="ISO8859-1" family="Times New Roman"> permet directement la superposition du trac\351 d'un champ d'\351l\351ments de contact avec ceux des solutions particuli\350res.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">DEplot(ED,y(x),x=-2..2,[[y(0)=-2],[y(0)=-1],[y(0)=0],[y(0)=1],[y(0)=2]],y=-2..2,linecolor=navy,color=orange,scaling=constrained,arrows=line,dirgrid=[25,25]);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group></Section><Section collapsed="true"><Title><Text-field layout="Heading 1" style="Heading 1"><Font encoding="ISO8859-1" family="Times New Roman"> M\351thode d'Euler-Cauchy</Font></Text-field></Title><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Mettons en \351vidence la solution particuli\350re </Font><Equation input-equation="y(0)=-1" style="2D Comment">NiMvLSUieUc2IyIiISwkIiIiISIi</Equation><Font family="Times New Roman"> pour x </Font><Equation input-equation="epsilon" style="2D Comment">NiMlKGVwc2lsb25H</Equation><Font family="Times New Roman"> [0; 1,6].</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Sol_par:=dsolve({ED,y(0)=-1},y(x));</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">plot([x,rhs(Sol_par),x=0..1.6]);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Ce trac\351 est exact car il a \351t\351 obtenu \340 l'aide de la solution g\351n\351rale. Obtenons maintenant une approximation de ce trac\351 en joignant les points que l'on obtient avec la m\351thode d'Euler-Cauchy. En fait, il s'agit d'approximer la courbe solution de l'\351quation diff\351rentielle </Font><Equation input-equation="dy/dx = `y'`;" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiJSN5J0c=</Equation><Font family="Times New Roman"> = </Font><Equation input-equation="f(x,y)" style="2D Comment">NiMtJSJmRzYkJSJ4RyUieUc=</Equation><Font family="Times New Roman"> avec la condition initiale </Font><Equation input-equation="y(x[0])=y[0]" style="2D Comment">NiMvLSUieUc2IyYlInhHNiMiIiEmRiVGKQ==</Equation><Font family="Times New Roman">.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Cette m\351thode repose sur le processus it\351ratif suivant. La condition initiale pr\351cise un premier point. Ce point est \351videmment exact. Soit (</Font><Equation input-equation="x[0], y[0]" style="2D Comment">NiQmJSJ4RzYjIiIhJiUieUdGJQ==</Equation><Font encoding="ISO8859-1" family="Times New Roman">) ce premier point. En ce point, la pente de la tangente \340 la courbe solution est donn\351e par f(</Font><Equation input-equation="x[0], y[0]" style="2D Comment">NiQmJSJ4RzYjIiIhJiUieUdGJQ==</Equation><Font encoding="ISO8859-1" family="Times New Roman">). Alors, l'\351quation de la tangente en ce point est</Font></Text-field><Text-field layout="_pstyle261" style="2D Comment"><Equation input-equation="y = `y'`(x[0])*(x-x[0])+y(x[0]);" style="2D Comment">NiMvJSJ5RywmKiYtJSN5J0c2IyYlInhHNiMiIiEiIiIsJkYrRi5GKiEiIkYuRi4tRiRGKUYu</Equation></Text-field><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">c'est-\340-dire</Font></Text-field><Text-field layout="_pstyle262" style="2D Comment"><Equation input-equation="y = f(x[0],y[0])*(x-x[0])+y[0];" style="2D Comment">NiMvJSJ5RywmKiYtJSJmRzYkJiUieEc2IyIiISZGJEYsIiIiLCZGK0YvRiohIiJGL0YvRi5GLw==</Equation></Text-field><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">L'expression (</Font><Equation input-equation="x-x[0]" style="2D Comment">NiMsJiUieEciIiImRiQ2IyIiISEiIg==</Equation><Font encoding="ISO8859-1" family="Times New Roman">) sera vue comme un accroissement d'abscisse h qui sera \253assez\273 petit. \300 cet accroissement, correspondra une valeur d'ordonn\351e jusqu'\340 la tangente </Font><Equation input-equation="y[1]= f(x[0],y[0])*h+y[0]" style="2D Comment">NiMvJiUieUc2IyIiIiwmKiYtJSJmRzYkJiUieEc2IyIiISZGJUYvRiclImhHRidGJ0YxRic=</Equation><Font encoding="ISO8859-1" family="Times New Roman">. On obtient ainsi un deuxi\350me point </Font><Equation input-equation="(x[1], y[1]) = (x[0]+h, f(x[0],y[0])*h+y[0]);" style="2D Comment">NiMvNiQmJSJ4RzYjIiIiJiUieUdGJzYkLCYmRiY2IyIiIUYoJSJoR0YoLCYqJi0lImZHNiRGLSZGKkYuRihGMEYoRihGNkYo</Equation><Font family="Times New Roman">.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">De m\352me, un troisi\350me point de coordonn\351es </Font><Equation input-equation="(x[2], y[2]) = (x[1]+h, f(x[1],y[1])*h+y[1])" style="2D Comment">NiMvNiQmJSJ4RzYjIiIjJiUieUdGJzYkLCYmRiY2IyIiIkYvJSJoR0YvLCYqJi0lImZHNiRGLSZGKkYuRi9GMEYvRi9GNkYv</Equation><Font encoding="ISO8859-1" family="Times New Roman"> sera obtenu \340 l'aide de la direction de la tangente passant par le deuxi\350me point f(</Font><Equation input-equation="x[1],y[1]" style="2D Comment">NiQmJSJ4RzYjIiIiJiUieUdGJQ==</Equation><Font family="Times New Roman">).</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">Et ainsi de suite: </Font><Equation input-equation="(x[n], y[n]) = (x[n-1]+h, f(x[n-1],y[n-1])*h+y[n-1])" style="2D Comment">NiMvNiQmJSJ4RzYjJSJuRyYlInlHRic2JCwmJkYmNiMsJkYoIiIiRjAhIiJGMCUiaEdGMCwmKiYtJSJmRzYkRi0mRipGLkYwRjJGMEYwRjhGMA==</Equation><Font family="Times New Roman">.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font family="Times New Roman" style="_cstyle295">REMARQUE</Font><Font encoding="ISO8859-1" family="Times New Roman">: La solution d'une \351quation diff\351rentielle est une fonction. La m\351thode d'Euler-Cauchy ne donne pas une fonction: elle permet seulement d'obtenir une s\351quence de couple (</Font><Font family="Times New Roman" style="_cstyle289">x</Font><Font family="Times New Roman">,<Font style="_cstyle291">y</Font><Font encoding="ISO8859-1">) qu'il suffit de relier de mani\350re appropri\351e pour approximer la courbe solution.</Font></Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Appliquons maintenant ce raisonnement pour obtenir une s\351rie de points que l'on reliera ensuite dans un trac\351 qui sera superpos\351 \340 celui de la solution analytique.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Automatisons le calcul d'un nombre n de couples ordonn\351es (</Font><Font family="Times New Roman" style="_cstyle290">x</Font><Font family="Times New Roman">,<Font style="_cstyle292">y</Font><Font encoding="ISO8859-1">). Rappelons-nous d'abord l'\351quation diff\351rentielle \340 r\351soudre.</Font></Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">ED;</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">La condition initiale impose le premier point.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">X[0]:=0;
Y[0]:=-1;
Points_Euler:=[X[0],Y[0]];</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">Posons un accroissement </Font><Equation input-equation="h=0,1" style="2D Comment">NiQvJSJoRyIiISIiIg==</Equation><Font family="Times New Roman">.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">h:=0.1;</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">R\351partissons le nombre suppl\351mentaires de points par le calcul suivant: la largeur de l'intervalle d'approximation [0; 1,6] divis\351e par la valeur de l'accroissement h.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">N:=(1.6-0)/h;</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">for n from 0 to N-1 do
 X[n+1]:=X[n]+h:
 Y[n+1]:=Y[n]+h*f(X[n],Y[n]):  # f(x,y) est la formule de calcul de la pente
 Tampon:=[X[n+1],Y[n+1]];
 Points_Euler:=Points_Euler,Tampon
od:</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Superposons  le trac\351 de ces points (sans les relier) avec celui de la courbe solution.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Sol:=dsolve({ED,y(0)=-1},y(x));
Courbe_solution:=plot([x,rhs(Sol),x=0..1.6],color=navy,thickness=2):
Points_approx:=plot([Points_Euler],style=point,symbol=circle,color=orange):
display([Courbe_solution,Points_approx]);</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">Diminuons le valeur de l'accroissement pour une seconde approximation.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Points_Euler:=[X[0],Y[0]];</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">h:=0.05;</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">N:=(1.6-0)/h;
for n from 0 to N-1 do
 X[n+1]:=X[n]+h:
 Y[n+1]:=Y[n]+h*f(X[n],Y[n]):  # f(x,y) est la formule de calcul de la pente
 Tampon:=[X[n+1],Y[n+1]];
 Points_Euler:=Points_Euler,Tampon
od:</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Sol:=dsolve({ED,y(0)=-1},y(x));
Courbe_solution:=plot([x,rhs(Sol),x=0..1.6],color=navy,thickness=2):
Points_approx:=plot([Points_Euler],style=point,symbol=circle,color=magenta):
display([Courbe_solution,Points_approx]);</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">Relions finalement ces points avec la macro-commande </Font><Font style="_cstyle293">pointplot</Font><Font family="Times New Roman"> de l'extension </Font><Font style="_cstyle294">plots</Font><Font family="Times New Roman">.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Points_approx:=pointplot([Points_Euler],connect=true,color=magenta):
display([Courbe_solution,Points_approx]);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group></Section><Section collapsed="true"><Title><Text-field layout="Heading 1" style="Heading 1"><Font encoding="ISO8859-1" family="Times New Roman"> M\351thode d'Euler-Cauchy am\351lior\351e ou m\351thode de Heun</Font></Text-field></Title><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Cette m\351thode a comme caract\351ristique que l'ordonn\351e du prochain point est calcul\351 non pas avec la pente de la tangente \340 la courbe solution du point courant mais plut\364t avec la moyenne arithm\351tique des pentes des tangentes \340 la courbe solution du point courant et du point suivant temporaire calcul\351 dans la direction donn\351e par la tangente au point suivant et ce, \340 partir de l'estimation de l'ordonn\351e du point courant.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Dans le cas de la m\351thode de Heun, on a:</Font></Text-field><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">   </Font><Equation input-equation="x[n+1] =x[n]+h" style="2D Comment">NiMvJiUieEc2IywmJSJuRyIiIkYpRiksJiZGJTYjRihGKSUiaEdGKQ==</Equation></Text-field><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">   </Font><Equation input-equation="u[n+1] = y[n]+ h*f(x[n],y[n])" style="2D Comment">NiMvJiUidUc2IywmJSJuRyIiIkYpRiksJiYlInlHNiNGKEYpKiYlImhHRiktJSJmRzYkJiUieEdGLUYrRilGKQ==</Equation></Text-field><Text-field layout="Normal" style="Normal"><Font family="Times New Roman">   </Font><Equation input-equation="y[n+1] = y[n]+ h*((f(x[n],y[n])+f(x[x+1],u[n+1]))/2)" style="2D Comment">NiMvJiUieUc2IywmJSJuRyIiIkYpRiksJiZGJTYjRihGKSomJSJoR0YpKiYsJi0lImZHNiQmJSJ4R0YsRitGKS1GMjYkJkY1NiMsJkY1RilGKUYpJiUidUdGJkYpRikiIiMhIiJGKUYp</Equation></Text-field><Text-field layout="Normal" style="Normal"/><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Pour bien automatiser le calcul des points de la courbe solution \340 estimer, automatisons d'abord la m\351thode d'Euler-Cauchy avec la proc\351dure suivante.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Euler:=proc(f::procedure,y0::realcons,Intervalle::range,h::realcons)
local n,N,Points_Euler,Tampon,X,Y; 
X[0]:=op(1,Intervalle); Y[0]:=y0;
Points_Euler:=[X[0],Y[0]]:  # Point de la condition initiale
N:=(op(2,Intervalle)-X[0])/h:
for n from 0 to N-1 do
 X[n+1]:=X[n]+h:
 Y[n+1]:=Y[n]+h*f(X[n],Y[n]):  # f(x,y) est la formule de calcul de la pente
 Tampon:=[X[n+1],Y[n+1]];
 Points_Euler:=Points_Euler,Tampon
od
end:</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Maintenant, automatisons l'algorithme de la m\351thode d'Euler-Cauchy am\351lior\351e, c'est-\340-dire de la m\351thode de Heun.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Heun:=proc(f::procedure,y0::realcons,Intervalle::range,h::realcons)
local n,N,Points_Heun,Tampon,X,Y,U; 
X[0]:=op(1,Intervalle); Y[0]:=y0;
Points_Heun:=[X[0],Y[0]]:  # Point de la condition initiale
N:=(op(2,Intervalle)-X[0])/h:
for n from 0 to N-1 do
 X[n+1]:=X[n]+h:
 U[n+1]:=Y[n]+h*f(X[n],Y[n]):  # f(x,y) est la formule de calcul de la pente
 Y[n+1]:=Y[n]+h/2*(f(X[n],Y[n])+f(X[n+1],U[n+1])):
 Tampon:=[X[n+1],Y[n+1]];
 Points_Heun:=Points_Heun,Tampon
od
end:</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Comparons maintenant la m\351thode de Heun avec celle d'Euler-Cauchy avec l'\351quation diff\351rentielle du d\351but </Font><Equation input-equation="dy/dx=-2*x-y" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiLCYqJiIiI0YmJSJ4R0YmRiglInlHRig=</Equation><Font family="Times New Roman"> avec comme condition initiale </Font><Equation input-equation="y(0)=-1" style="2D Comment">NiMvLSUieUc2IyIiISwkIiIiISIi</Equation><Font family="Times New Roman">.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">f:=(x,y)-&gt;-2*x-y;</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Euler_Approx:=plot([Euler(f,-1,0..1.6,0.1)],style=point,symbol=circle,color=magenta):
Heun_Approx:=plot([Heun(f,-1,0..1.6,0.1)],style=point,symbol=circle,color=green):
Champ:=dfieldplot(ED,[y(x)],
x=0..1.6,y=-2..-0.5,arrows=line,dirgrid=[15,15],scaling=constrained,color=orange):
display([Heun_Approx,Euler_Approx,Courbe_solution,Champ]);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">On constate effectivement que la m\351thode de Heun (points verts) am\351liore beaucoup l'estimation de la courbe solution obtenue avec la m\351thode d'Euler-Cauchy (points magenta).</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group></Section><Section collapsed="true"><Title><Text-field layout="Heading 1" style="Heading 1"><Font encoding="ISO8859-1" family="Times New Roman"> M\351thode de Runge-Kutta</Font></Text-field></Title><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">La m\351thode de Runge-Kutta du quatri\350me ordre am\351liore davantage la m\351thode d'Euler am\351lior\351e mais les calculs sont encore beaucoup plus \351labor\351s. Cette m\351thode repose aussi en quelque sorte sur un calcul de moyenne arithm\351tique de pentes.  Pr\351sentons, sans autres explications, la proc\351dure automatisant l'algorithme de Runge-Kutta.</Font></Text-field><Text-field layout="Normal" style="Normal"/><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">Runge_Kutta:=proc(f::procedure,y0::realcons,Intervalle::range,h::realcons)
local n,N,p,Points_Runge_Kutta,q,r,s,Tampon,X,Y; 
X[0]:=op(1,Intervalle); Y[0]:=y0;
Points_Runge_Kutta:=[X[0],Y[0]]:  # Point de la condition initiale
N:=(op(2,Intervalle)-X[0])/h:
for n from 0 to N-1 do
 X[n+1]:=X[n]+h:
 p[n]:=f(X[n],Y[n]):
 q[n]:=f(X[n]+h/2,Y[n]+h/2*p[n]):
 r[n]:=f(X[n]+h/2,Y[n]+h/2*q[n]):
 s[n]:=f(X[n]+h,Y[n]+h*r[n]):
 Y[n+1]:=Y[n]+h/6*(p[n]+2*q[n]+2*r[n]+s[n]):
 Tampon:=[X[n+1],Y[n+1]];
 Points_Runge_Kutta:=Points_Runge_Kutta,Tampon
od
end:</Text-field></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Pour l'\351quation diff\351rentielle </Font><Equation input-equation="dy/dx=-2*x-y" style="2D Comment">NiMvKiYlI2R5RyIiIiUjZHhHISIiLCYqJiIiI0YmJSJ4R0YmRiglInlHRig=</Equation><Font encoding="ISO8859-1" family="Times New Roman">, la m\351thode de Heun montrait \340 la section pr\351c\351dente que les points calcul\351s \351pousaient d\351j\340, de mani\350re remarquable, la courbe solution. Le degr\351 de pr\351cision atteint avec cette m\351thode a pu \352tre appr\351ci\351 par une approche graphique \340 l'\351gard de la m\351thode d'Euler. Par contre, avec la m\351thode du Runge-Kutta, le degr\351 de pr\351cision atteint \340 l'\351gard de la m\351thode de Heun est difficilement appr\351ciable graphiquement (\340 l'\351cran). En effet, constatons que les trac\351s des courbes en reliant les points calcul\351s par les m\351thodes de Heun et de Runge-Kutta et la courbe solution se superposent presque parfaitement compte tenu de la r\351solution \351cran. Il est n\351cessaire de proc\351der au grosissant maximum de l'affichage (Ctrl-6), pour pouvoir  \253 visualiser \273 l'augmentation de la pr\351cision.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input">A:=array(1..2):
C1:=pointplot([Heun(f,-1,0..1.6,0.1)],connect=true,color=orange):
C2:=pointplot([Runge_Kutta(f,-1,0..1.6,0.1)],connect=true,color=cyan):
A[1]:=display([Courbe_solution,C1,C2]):
A[2]:=display([Courbe_solution,C2,C1]):
display(A);</Text-field></Input></Group><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group><Text-field layout="Normal" style="Normal"><Font encoding="ISO8859-1" family="Times New Roman">Seul un calcul num\351rique pourra permettre clairement une comparaison entre les degr\351s de pr\351cision atteint par chaque m\351thode \340 l'\351gard de la courbe solution.</Font></Text-field><Group><Input><Text-field layout="Normal" prompt="&gt; " style="Maple Input"/></Input></Group></Section><Text-field/></Worksheet>